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x + 2y + z = 8 ....(1)

2x - y + 2z = 6 ....(2)

x + 3y - z = 4 ....(3)

  • Ubah bentuk pers. (1)

x + 2y + z = 8

x + z = 8 - 2y

x = 8 - 2y - z ...(4)

  • Substitusi kan pers. (4) ke pers. (2)

2x - y + 2z = 6

2(8 - 2y - z) - y + 2z = 6

16 - 4y - 2z - y + 2z = 6

16 - 5y = 6

-5y = 6 - 16

-5y = -10

y = 10/5

y = 2

  • Substitusi pers. (4) ke pers. (3)

x + 3y - z = 4

8 - 2y - z + 3y - z = 4

y - 2z = -4 ....(5)

  • Substitusi nilai y ke pers. (5)

y - 2z = -4

2 - 2z = -4

-2z = -4 - 2

-2z = -6

z = 6/2

z = 3

  • Substitusi nilai z dan y ke pers. (4)

x = 8 - 2y - z

x = 8 - 2(2) - 3

x = 8 - 4 - 3

x = 4 - 3

x = 1

  • Nilai 2x + 3y - z

2x + 3y - z

= 2(1) + 3(2) - 3

= 2 + 6 - 3

= 8 - 3

= 5 (E.)

Jawaban : E. 5

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